Using the ideal gas law, we can calculate the maximum volume of oxygen at room temperature and pressure.
First, we need to calculate the moles of oxygen produced from 0.50 mol of potassium chlorate (V):
0.50 mol KCIO3 x (2 mol O2/2 mol KCIO3) = 0.50 mol O2
Next, we need to calculate the volume of 0.50 mol of oxygen at room temperature and pressure using the ideal gas law:
V = nRT/P
where V is the volume, n is the number of moles, R is the universal gas constant (0.0821 atm∙L/mol∙K), T is the temperature (298 K) and P is the pressure (1 atm).
V = (0.50 mol)(0.0821 atm∙L/mol∙K)(298 K)/(1 atm)
V = 11.83 L
Therefore, the maximum volume of oxygen, measured in dm3, which could be obtained by heating 0.50 mol potassium chlorate(V) at room temperature and pressure is 11.83 dm3.
Hope it helps.
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