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AQA GCSE Chemistry 8462 - Paper 2 - 12th June 2019

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4000 something

Original post by Khyake

what did you guys get for the volume of oxygen question

does anyone remember the values of the volumes in the 4 mark unreacted oxygen questjon?

OP

Original post by Anthos

I found the paper better than Biology 2, that’s for sure!

:woo:

That's great to hear! What's up next for you? :smile:

:smile:

Original post by happy.pirhana

does anyone remember the values of the volumes in the 4 mark unreacted oxygen questjon?

it might of been 3.6dm³ and 7.25dm³ I think

TSR Community Staff

How did you guys find it today?

Anyone get 1500cm^3 for the oxygen not reacted? I got 6 moles of oxygen.

Original post by 8472

:woo:

That's great to hear! What's up next for you? :smile:

:smile:

Geography tomorrow and Physics Friday.

I found that meh

I found it quite hard😭

Original post by Anthos

Geography tomorrow and Physics Friday.

Good luck! I have the same!! Schools doing a revision session this after noon for geog ahh

username4783232

Funny question - you see, I didn't even try it

Original post by Khyake

what did you guys get for the volume of oxygen question

username4296552

1250

livingnightshade

what did u guys write for the finding mass of dissolved substances question (the plan a practical one)??

What did you get for the untracked oxygen?

username4296552

1250

Original post by jduxie4414

What did you get for the untracked oxygen?

I did this;

3.6mol / 24 (molar gas constant) = 0.15 mol

0.15 mol * 5/3 = 0.25 mol of oxygen
0.25 * 24 = 6 dm^3
So 1.5 dm^3 spare
1.5*1000 = 1500cm^3

Edit: it was 1.25dm^3 spare so - 1.25* 1000 = 1250cm^3

(edited 4 years ago)

For the oxygen question, I believe the correct answer is 1250cm^3
The equation had 5 moles of oxygen reacting to produce 3 moles of carbon dioxide. The values given were 7.25 dm^3 of oxygen and 3.6 dm^3 of carbon dioxide produced.
To find the volume of oxygen that reacted, you do 3.6*(5/3) to get 6 dm^3 of oxygen. This, taken away from the initial volume of oxygen gave us 1.25 dm^3 of unreacted oxygen.
1.25 dm^3 = 1250 cm^3

Original post by xspx

For the oxygen question, I believe the correct answer is 1250cm^3
The equation had 5 moles of oxygen reacting to produce 3 moles of carbon dioxide. The values given were 7.25 dm^3 of oxygen and 3.6 dm^3 of carbon dioxide produced.
To find the volume of oxygen that reacted, you do 3.6*(5/3) to get 6 dm^3 of oxygen. This, taken away from the initial volume of oxygen gave us 1.25 dm^3 of unreacted oxygen.
1.25 dm^3 = 1250 cm^3

Oh it was 7.25 not 7.5? Damn stupid mistakes.

No one has included the water for oxygen question...?

That was an exam sent from the gods. Piss easy. Bagged a 9 ez.

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