Help! So I got 2 marks out of 4 ( I understand the first two steps… But how do I know the formula of the saturated product is C40H78 I mean I thought it was the general formula of an alkane CnH2n+2… But nope. So I think it’s something to do with the two rings and branched chain but I’m struggling as to how I would know what the structure looks like in order to determine the 78 Hs
I get that part… but I don’t get how I know it’s c40H56
Because you have lost 23 H due to the double bonds, and by having a ring, 2 carbons lose 1 H off of them to create a bond between them - this happens twice as there are 2 rings, so 4 H are lost Assuming it's an alkane with 40 C, it should have 82 H (using the formula) 82 -22-4=56