ik that in V= W/Q, Q is the charge that is being moved in an electric field.
But in E=kQ/r^(2), Q is the charge that creates an electric field??
so in the case where we direct a high energy alpha particle to a gold nucleus, whose Q are we going take in the equation: E= kQ/r^(2) ?
aren't the electric fields of both the aplha particle and gold nucleus interacting and producing a final electric field? so why do we then, only take charge of the gold in the equation?