I'm Stuck understanding what I've done wrong for the first part of this question:
So it's the oxidation half equation which I'm Puzzled on:
I started on Cl2 = ClO^-
Then I balenced out the Chlorines:
Cl2 = 2ClO-
Then I added 2 Moles of water to the RHS:
2H20 + Cl2 = 2ClO-
Then I Balenced out the charges:
2H20 +Cl2 = 2CLO- + 4H+ +2e-
on the RHS of the mark scheme it says: "Allow Cl2 + 2H2O 2ClO– + 2e"
But I have no clue on why they didn't add 4 protons onto the other side to balance the charges
Please help.