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Make a balanced symbol equation, using the data from this experiment.
Reactants
CaCl2= 666g
Products
Ca = 240g
Cl2= 426g

Reply 1

Ã„ries

13

calcium: 240/40.1 = 5.985 = 6 mol
chlorine: 426/(35.5x2) = 6 mol
mole ratio of Ca(s) and Cl2(g) = 6:6 = 1:1
so the empirical formula of calcium chloride reactant is CaCl2

(edited 8 months ago)

OP

I'm still confused

OP

Original post by TheGingerCarrot

OMG, that makes soooo much more sense now. I wasn't sure what they were asking me to do thank you!!!! :smile:

Reply 5

TheGingerCarrot

8

Original post by Blackrose06

OMG, that makes soooo much more sense now. I wasn't sure what they were asking me to do thank you!!!! :smile:

Ohhhhhhh I've just read that back and you state the reactant is CaCl2 and the products are Ca and Cl2, the Math is correct but it's for the decomposition of CaCl2 so equation is actually the reverse. I always misread when I did my A-level Chem questions and I still do to this day :biggrin:

6Cacl2 --> 6Ca + 6Cl2

(edited 8 months ago)

Reply 6

Blackrose06

OP

16

Original post by TheGingerCarrot

Ohhhhhhh I've just read that back and you state the reactant is CaCl2 and the products are Ca and Cl2, the Math is correct but it's for the decomposition of CaCl2 so equation is actually the reverse. I always misread when I did my A-level Chem questions and I still do to this day :biggrin:

6Cacl2 --> 6Ca + 6Cl2

I got that, so I changed it round anyway :smile:

. Thanks again!

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