\displaystyle \frac{secx-1}{tanx} = \frac{\frac1{cosx}-1}{\frac{sinx}{cosx}} = \frac{\frac{1-cosx}{cosx}}{\frac{sinx}{cosx}}=\frac{1-cosx}{sinx}=\frac{(1-cosx)(1+cosx)}{sinx(1+cosx)}}
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
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Last reply 4 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71