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AQA CHEM4 - 13th June 2012

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Reply 780
Original post by lamalas600
I think it's just Ni/H2


i mean with lialh4
Reply 781
what does this mean???
"increases (exponentially) allow straight line but not curve" help
its about how rate constant varies with temperature
Reply 782
Original post by g00d4u
what does this mean???
"increases (exponentially) allow straight line but not curve" help
its about how rate constant varies with temperature


makes no sense, if it increases exponentially a graph would be a curve
Reply 783
sketch a graph to show how the value of the rate constant varies with temperature. I drew a curve but in the mark scheme its not allowed. (jan08 q6b):confused:
Original post by shuaib786
When adding H+ ions into a buffer solution, the equilibrium shifts to the right hand side.
When adding OH- ions into a buffer solution, the equilibrium shifts to the left hand side.

Please can someone correct me here or confirm it right.


Opposite way round, when adding OH- shifts to the right, as it reacts with the acid producing more reactants
Original post by sconter
makes no sense, if it increases exponentially a graph would be a curve


if the graph were a natural log graph then it would be a straight line.

two possible things :

the axis on the temperature scale isn't uniform, meaning a straight line would indicate exponential increase
the graph is a natural log graph

temperature does increase exponentially with k
Reply 786
Original post by g00d4u
what does this mean???
"increases (exponentially) allow straight line but not curve" help
its about how rate constant varies with temperature


Original post by sconter
makes no sense, if it increases exponentially a graph would be a curve

That's what I I was thinking lol
Original post by g00d4u
sketch a graph to show how the value of the rate constant varies with temperature. I drew a curve but in the mark scheme its not allowed. (jan08 q6b):confused:


It's a curve, anything that suggests otherwise is stupid!
Original post by lamalas600
Opposite way round, when adding OH- shifts to the right, as it reacts with the acid producing more reactants


lol, so they both shift to the right then???
Original post by shuaib786
lol, so they both shift to the right then???


When adding H+ if shifts to the left (reacts with A-) producing more product
Original post by lamalas600
When adding H+ if shifts to the left (reacts with A-) producing more product


Im kinda confused, explain question 3 e) from jan 2012??
Reply 790
Original post by shuaib786
When adding H+ ions into a buffer solution, the equilibrium shifts to the right hand side.
When adding OH- ions into a buffer solution, the equilibrium shifts to the left hand side.

Please can someone correct me here or confirm it right.


when adding either H+ or OH-, equilibrium shifts to the right

(when you have an basic buffer: weak base and salt when strong acid added
NH3 + H2SO4 >< NH4+ + HSO4- if you add OH- to that, it reacts with the NH4+ reducing the concentration of that, so equilibrium displaces to the right, if that makes sense?)

Dont know if my equations are correct but i hope the principle helps
Reply 791
Original post by Bubbles94
CHEM5 will be alright i think.. but CHEM4 was terrible...
be careful about resitting CHEM4.. its so difficult to revise alongside CHEM5.. and if you put too much attention on CHEM4.. you could mess up CHEM5, and we only get one shot at CHEM5 :/


i agree with that. havent touched chem5 haha. i flopped chem 4 in jan, got me 70% chem5 is impossible for me. i got a solid E in the jan 12 paper chem 5 practise LOOOOOL! with UMS conversions.. :s-smilie:
Reply 792
Original post by small'un
when adding either H+ or OH-, equilibrium shifts to the right

(when you have an basic buffer: weak base and salt when strong acid added
NH3 + H2SO4 >< NH4+ + HSO4- if you add OH- to that, it reacts with the NH4+ reducing the concentration of that, so equilibrium displaces to the right, if that makes sense?)

Dont know if my equations are correct but i hope the principle helps


Your equations make sense :smile:
Original post by shuaib786
Im kinda confused, explain question 3 e) from jan 2012??


I'm wrong sorry made a mistake, How do i access jan 2012 :smile:?
Can some one explain the marking points when H+ or OH- ions are added to a buffer solution please. (I.e. when they ask for the qualitative description with eqm stuff in the mark scheme).
Original post by lamalas600
I'm wrong sorry made a mistake, How do i access jan 2012 :smile:?


here 3 e) plzzz???
Original post by small'un
when adding either H+ or OH-, equilibrium shifts to the right

(when you have an basic buffer: weak base and salt when strong acid added
NH3 + H2SO4 >< NH4+ + HSO4- if you add OH- to that, it reacts with the NH4+ reducing the concentration of that, so equilibrium displaces to the right, if that makes sense?)

Dont know if my equations are correct but i hope the principle helps


Thanks and thanks for the example to.
Reply 797
Original post by kontemptXD
Can some one explain the marking points when H+ or OH- ions are added to a buffer solution please. (I.e. when they ask for the qualitative description with eqm stuff in the mark scheme).


If adding OH- it reacts with the acid formed [conjugate base] (whatever is given in the question, it will usually tell you to write the equation before)

If adding H+, it reacts with the base formed [conjugate acid] (same for this)

So the equilibrium displaces to the right
Original post by g00d4u
what does this mean???
"increases (exponentially) allow straight line but not curve" help
its about how rate constant varies with temperature


This might be awkwardly late :tongue: but it's a curve according to the Jan 2012 paper!

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