Core 3- Trig
Maths and statistics discussion, revision, exam and homework help.
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Core 3- Trig[sec(x) - 1 ]/tan(x) = [ tan (x)]/ sec(x) +1
So, i have to prove this identity is true. Ive managed to show it by dividing both sides by one of the sides, however i cant think how to start from either the left or right, and work myself to the other side. Any help would be awesome
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Re: Core 3- Trig(Original post by antonio108)
[sec(x) - 1 ]/tan(x) = [ tan (x)]/ sec(x) +1
So, i have to prove this identity is true. Ive managed to show it by dividing both sides by one of the sides, however i cant think how to start from either the left or right, and work myself to the other side. Any help would be awesome
LHS =
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Re: Core 3- TrigSeveral methods, here is mine.
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![\frac{sec-1}{tan} = [\frac{1}{cos} - 1]\frac{cos}{sin} = \frac{1-cos}{sin} = \frac{1-cos^2}{sin(1+cos)} = \frac{sin}{1+cos} = \frac{tan}{sec+1}](http://www.thestudentroom.co.uk/latexrender/pictures/c2/c2753c0219ccacea87a21114413a8dcb.png "\frac{sec-1}{tan} = [\frac{1}{cos} - 1]\frac{cos}{sin} = \frac{1-cos}{sin} = \frac{1-cos^2}{sin(1+cos)} = \frac{sin}{1+cos} = \frac{tan}{sec+1}")
