Physic Light
hello,
Anyone could you please help me with this question:
The diagram represents some energy levels of the mercury atom.
0
-1.6
-5.5 Energy/eV
-10.4
charge of electron = 1.6 × 10–19 C
the Planck constant = 6.6 × 10–34 J s
speed of light in vacuo = 3.0 × 108 ms–1
1) A transition between which two energy levels in the mercury atom will give rise to an emission line of wavelength 320nm?
Anyone could you please help me with this question:
The diagram represents some energy levels of the mercury atom.
0
-1.6
-5.5 Energy/eV
-10.4
charge of electron = 1.6 × 10–19 C
the Planck constant = 6.6 × 10–34 J s
speed of light in vacuo = 3.0 × 108 ms–1
1) A transition between which two energy levels in the mercury atom will give rise to an emission line of wavelength 320nm?
e = hf
f = v/lamba
so, e = (h*v)/lamba, where v = speed of light and h is planck's constant
f = v/lamba
so, e = (h*v)/lamba, where v = speed of light and h is planck's constant
Original post by boromir9111
e = hf
f = v/lamba
so, e = (h*v)/lamba, where v = speed of light and h is planck's constant
f = v/lamba
so, e = (h*v)/lamba, where v = speed of light and h is planck's constant
Thank you .
But why v is the speedof light?
But why v is the speedof light?
hello,
Does anyone know what it means by stopping potential?
Does anyone know what it means by stopping potential?
Original post by valerieyong
hello,
Does anyone know what it means by stopping potential?
Does anyone know what it means by stopping potential?
Google is your friend,
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