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Transforming graphs-help!

I have been given the function f(x)=x2
I need to sketch a graph for y=-f(x+2) and find the maximum and minimum points.
I've managed to find the maximum point which is (-2,0) but in the answers, it also states the graph also crosses at (0,-4) and I have no idea how they got that. By the way, I'm supposed to use GCSE knowledge for this!
(edited 10 years ago)
So your equation is y=(x+2)2y=-(x+2)^2

Substitute x = 0 into this equation and see what you get!
Original post by bobbricks
I have been given the function f(x)=x2
I need to sketch a graph for y=-f(x+2) and find the maximum and minimum points.
I've managed to find the maximum point which is (-2,0) but in the answers, it also states the graph also crosses at (0,-4) and I have no idea how they got that. By the way, I'm supposed to use GCSE knowledge for this!

Remember, anything in the brackets affects the x axis, and outside the bracket affects the y axis.
Reply 3
Original post by Mr M
So your equation is y=(x+2)2y=-(x+2)^2

Substitute x = 0 into this equation and see what you get!


Thanks- it seems quite simple now :biggrin:

There's one more question that's been confusing me-
f(x)=x2

I need to find the minimum/maximum point and where they cut the x and y axis for this equation:
y=f(2x+1)-1

So far I've managed to find (-2,-1) and (0,15) but there's two more in the answers which I'm not sure how to find (-3/2,0) and (-5/2,0)

EDIT: never mind- I've managed to find out via factorising! :biggrin:
(edited 10 years ago)
Original post by bobbricks
Thanks- it seems quite simple now :biggrin:

There's one more question that's been confusing me-
f(x)=x2

I need to find the minimum/maximum point and where they cut the x and y axis for this equation:
y=f(2x+1)-1

So far I've managed to find (-2,-1) and (0,15) but there's two more in the answers which I'm not sure how to find (-3/2,0) and (-5/2,0)

EDIT: never mind- I've managed to find out via factorising! :biggrin:


Good.

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