Co-Ordination Chem Question.

Hi all,

I have a question.

For [NiBr₄]^2-

What is the number of d electrons on the metal ion and what is the valency of that metal ion.


I'm coming up with oxidation number of +2 for Ni and its group 10 so 10-2 = 8 d electrons.

For valency I'm just counting the amount of periods there is from the starting d-block element Scandium.

Am I doing this correctly?

Yes for oxidation number and d electrons.

Valency is simply the ionic charge on the Ni ...

Thank you, so the valency is 2?

correct +2

What I don't understand is the technique used to find this, surely it can't always be = to the oxidation number?

Is the valency still 2 in [Ni(CN)₄]^2-?

Yes it is ... +2