I know that by increasing the concentration of Cu, which is the cathode, and keeping the concentration of Zn constant, results in less potential cell difference, and therefore the voltage should increase.
So I am assuming it is the opposite for the Zn, which is the anode, and therefore the voltage would decrease as the Zn concentration increases.
You've got the idea right, but the terminology needs a bit of work.
According to Le Chatelier, increasing the conc. of either metal will make that half cell more positive. Since voltage = electrode potential (more positive) minus E. Pot. (more negative), then the voltage behaves as you said.
You've got the idea right, but the terminology needs a bit of work.
According to Le Chatelier, increasing the conc. of either metal will make that half cell more positive. Since voltage = electrode potential (more positive) minus E. Pot. (more negative), then the voltage behaves as you said.