Physics GCSE question

Please could I have help on the highlighted part of this question? Since both lamps are exactly the same and have the same resistance, surely the voltage is spilt evenly so both x and y have the same brightness? Thank you!

In a series circuit, voltage is split evenly between components that have the same resistance. As there are more bulbs in lamp X than in lamp Y, the voltage of each bulb in circuit X is lower than the voltage of each bulb in circuit Y because the same number of volts is being shared between a greater number of components. Because each bulb in lamp Y has a greater voltage than each bulb in lamp X, a bulb in lamp Y will be brighter than a bulb in lamp X. Greater voltage = brighter. Hope that helps!

since you have less lamps in y,there would be less resistance,as resistance in series circuit is R1+R2+R3.......,so using the equation p=v^2/R,the value of p (power) would be greater for each lamp

physics sure is fun huh?

But since the resistance of the bulbs are the same, how would the resistance of Lamp Y be less if it is 350 ohms?

In a series circuit the total resistance of the circuit is calculated by adding the resistances of each component in the circuit. Lamp X would have a total resistance of 7 x 390 = 2730 ohms because there are 7 bulbs in the lamp each of which have a resistance of 390 ohms. Lamp Y would have a total resistance of 5 x 390 = 1950 ohms because there are 5 bulbs in the lamp each of which have a resistance of 390 ohms. I hope that makes more sense.

Ohh yess that makes much more sense, thank you very much!!