I know the bond angles of molecules for a certain amount of electron pairs that don't involve lone pairs, however, when it comes to determine the bond angles INCLUDING the lone pairs I start to get confused.
So far I know that for each lone pair (in a tetrahedral arrangement) I have to subtract by 2.5 degrees. But what about for 3, 5 and 6 electron pairs?
I know the bond angles of molecules for a certain amount of electron pairs that don't involve lone pairs, however, when it comes to determine the bond angles INCLUDING the lone pairs I start to get confused.
So far I know that for each lone pair (in a tetrahedral arrangement) I have to subtract by 2.5 degrees. But what about for 3, 5 and 6 electron pairs?
I know the bond angles of molecules for a certain amount of electron pairs that don't involve lone pairs, however, when it comes to determine the bond angles INCLUDING the lone pairs I start to get confused.
So far I know that for each lone pair (in a tetrahedral arrangement) I have to subtract by 2.5 degrees. But what about for 3, 5 and 6 electron pairs?
You should know how to work out the actual shape first:
1) Get the group number of the primary element 2) If its a negative charge, add that to the group number from 1) or subtract the positive charge 3) Add the bonded pairs 4) Divide by 2 to get the bonded pairs 5) Now subtract the bonded pairs by the number of bonds to find the loan pairs.
As for the bond angles, you just need to remember each bond angle along with the shape.
Also, remember that bonded pairss repel the most, then its bonded and lone pairs and lone pairs repel each other the least which is the cause of the specific bond angle (sometimes asked in exams)
If the first part doesnt make sense let me know and I'll give an example
You will have to remember the angles. calculating it is not that easy.. just check the syllabus, take a few minutes to learn the angles for the molecles or arrangement of molecules mentioned in syllabus and solve some topical pastpapers for them. This will hardly take an hour
You should know how to work out the actual shape first:
1) Get the group number of the primary element 2) If its a negative charge, add that to the group number from 1) or subtract the positive charge 3) Add the bonded pairs 4) Divide by 2 to get the bonded pairs 5) Now subtract the bonded pairs by the number of bonds to find the loan pairs.
As for the bond angles, you just need to remember each bond angle along with the shape.
Also, remember that bonded pairss repel the most, then its bonded and lone pairs and lone pairs repel each other the least which is the cause of the specific bond angle (sometimes asked in exams)
If the first part doesnt make sense let me know and I'll give an example
Hey, thank you.
I'm just confused because in the CGP book it says SO2 has a bond angle of 119 degrees, instead of 120 degrees. I understand why it is less (because of the lone pair). however, will I need to know how to calculate this? Or is the bond angle always 119 degrees if there's just one lone pair within the 3 electron pairs around the central atom? Additionally, what would be the angle if there was 2 lone pairs instead? Am I making sense?
I'm just confused because in the CGP book it says SO2 has a bond angle of 119 degrees, instead of 120 degrees. I understand why it is less (because of the lone pair). however, will I need to know how to calculate this? Or is the bond angle always 119 degrees if there's just one lone pair within the 3 electron pairs around the central atom? Additionally, what would be the angle if there was 2 lone pairs instead? Am I making sense?