I was given the question: "Explain why the centre of mass of the beam in the diagram must be vertically below A". (see my reply for link to the image...) my answer: both cables meet at A for which they are perpendicular to each other and the beam is in equilibrium and stationary. Hence centre mass is at A, as it's component of tension is directly above the weight of beam for which it's angle is 90 degrees from the horizontal
I was given the question: "Explain why the centre of mass of the beam in the diagram must be vertically below A". (see my reply for link to the image...) my answer: both cables meet at A for which they are perpendicular to each other and the beam is in equilibrium and stationary. Hence centre mass is at A, as it's component of tension is directly above the weight of beam for which it's angle is 90 degrees from the horizontal
I dont think you need to mention the angle the two cables meet. It is however important that the beam is stationary and in equilibrium. The beam can only be in equilibrium if the supporting force is on a line passing through the centre of mass.