Also, where you have inaccuracy from the measuring tools, you might also get it from human error. Can someone remind me how to find the accuracy when you take 5 readings, say:
5.23, 5.24, 5.20, 5.24, 5.22
Would it be the range divided by the average?
(5.24-5.20)/[(5.23 + 5.24 + 5.20 + 5.24 + 5.22)/5] which is 0.765%
Would this then override the accuracy of the equipment, say meade a measurement like 5.32 +/- 0.005? Or would you add it? It seems wrong to add it but I just want to check.
Also is it correct to only do this for results which have relied on humans recording things (eg. stopwatch compared to scales where there is no possibility for human error).
Thanks again, rep definatly awarded.