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How is -4 divided by -4 = -8

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Original post by abc:)
Lol I'm being destroyed :laugh: I really need this explaining to me


Easy target and I'm bored tbh


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Original post by drandy76
Technically speaking it is getting smaller if we're only concerned with the magnitudes


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But we're not :tongue:
Original post by Student403
But we're not :tongue:


Traitor :frown:


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I think what's happened is the divide sign on your calculator has been rubbed out a bit and now looks like a minus sign.
Original post by tanyapotter
I think what's happened is the divide sign on your calculator has been rubbed out a bit and now looks like a minus sign.


4(4)=0-4-(-4)=0
Original post by Kvothe the arcane
4(4)=0-4-(-4)=0


He still could have typed -4-4 into his calculator.
Original post by NoahMal
-4/-4 Firstly two negatives cancel out hence its 4/4 which is 1 therefore by mathematical induction it does not equal -8....


This is correct. I agree wholeheartedly.
Reply 47
I'm gonna start off by assuming that xx=k\frac{x}{x} = k where k is some constant.

    x=kx    (k1)x=0\iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x=0x = 0.

From our original equation we have 00=k\frac{0}{0}= k and we know that anything divided by 0 is infinity, and so     ±=k\iff \pm \infty = k.

We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k=k = - \infty.

Infinity is just an 88 rotated 90 or 270 degrees, so k=8k = -8 and it follows that xx=8\frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.
(edited 7 years ago)
Original post by Ayman!
I'm gonna start off by assuming that xx=k\frac{x}{x} = k where k is some constant.

    x=kx    (k1)x=0\iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x=0x = 0.

From our original equation we have 00=k\frac{0}{0}= k and we know that anything divided by 0 is infinity, and so     ±=k\iff \pm \infty = k.

We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k=k = - \infty.

Infinity is just an 88 rotated 90 or 270 degrees, so k=8k = -8 and it follows that xx=8\frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.


Today is a good day in maths history
Reply 49
Original post by Ayman!
I'm gonna start off by assuming that xx=k\frac{x}{x} = k where k is some constant.

    x=kx    (k1)x=0\iff x=kx \iff \left ( k-1 \right )x = 0 and so we now know that x=0x = 0.

From our original equation we have 00=k\frac{0}{0}= k and we know that anything divided by 0 is infinity, and so     ±=k\iff \pm \infty = k.

We reject the positive solution because x = -4 in our original example and so it must be negative infinity: k=k = - \infty.

Infinity is just an 88 rotated 90 or 270 degrees, so k=8k = -8 and it follows that xx=8\frac{x}{x} = -8, hence -4 divided by -4 is indeed -8.


nah you forgot you have to rotate the k by 90 or 270 degrees as well

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