value of k

y=16x-kx^2 k is a constant
I have this curve with a line y=-1/2+18
I have a length of line and some coordinates where they cross.

I am asked to show that k = 3.
How do I go about this question? Should I put both equations equal to each other and solve? Or should this be done by simultaneous equation solving -quadratic and linear?
thanks

Reply 1

steve2005

17

lemonz

y=16x-kx^2 k is a constant
I have this curve with a line y=-1/2+18
I have a length of line and some coordinates where they cross.

I am asked to show that k = 3.
How do I go about this question? Should I put both equations equal to each other and solve? Or should this be done by simultaneous equation solving -quadratic and linear?
thanks

I guess your line is

y=\frac{-x}{2}+18

Is my guess correct?

Reply 2

lemonz

OP

yes
y=-1/2x+18
good guess

Reply 3

steve2005

17

lemonz

y=16x-kx^2 k is a constant
I have this curve with a line y=-1/2+18
I have a length of line and some coordinates where they cross.

I am asked to show that k = 3.
How do I go about this question? Should I put both equations equal to each other and solve? Or should this be done by simultaneous equation solving -quadratic and linear?
thanks

You should try something and see if it gets you anywhere. If what you do does not help then try something else.

Reply 4

lemonz

OP

ok - 16x-kx^2 is a quadratic that can be factorized with difference of two squares
x=+-4
input into original equation
and k = 3

value of k

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