Mathematics
The curve and the line given by equations kx^2-xy (k 1)x=1-k/2x y=1Where k is non-zero constant, intersect at single point.a. Find the value of k
Original post by studioaisha
The curve and the line given by equations kx^2-xy (k 1)x=1-k/2x y=1Where k is non-zero constant, intersect at single point.a. Find the value of k
Whst have you tried?
I did try many times, but couldn't find the solution
The curve and the line given by the equations
kx^2-xy+(k+1)x=1
(-k/2)× +y=1
Where k is a non-zero constant, intersect at a single point. Find the value of k.
Answer : k= -2
How? Please if you could explain to me.
How to substitute y=(k/2)+1 and get the value of k?
kx^2-xy+(k+1)x=1
(-k/2)× +y=1
Where k is a non-zero constant, intersect at a single point. Find the value of k.
Answer : k= -2
How? Please if you could explain to me.
How to substitute y=(k/2)+1 and get the value of k?
Original post by studioaisha
The curve and the line given by the equations
kx^2-xy+(k+1)x=1
(-k/2)× +y=1
Where k is a non-zero constant, intersect at a single point. Find the value of k.
Answer : k= -2
How? Please if you could explain to me.
How to substitute y=(k/2)+1 and get the value of k?
kx^2-xy+(k+1)x=1
(-k/2)× +y=1
Where k is a non-zero constant, intersect at a single point. Find the value of k.
Answer : k= -2
How? Please if you could explain to me.
How to substitute y=(k/2)+1 and get the value of k?
when you substitute it into the other equation u wanna do b^2-4ac=0 because they only intersect at one point.
Tell me if you still dont understand I'll explain further
Tell me if you still dont understand I'll explain further
I really appreciate this explanation. You have made my mind as clear as crystal glass. Thank you ever soo much :
Original post by studioaisha
The curve and the line given by equations kx^2-xy (k 1)x=1-k/2x y=1Where k is non-zero constant, intersect at single point.a. Find the value of k
Can you solve it's second part.
Give the coordinates of the point of intersection of the line and the curve.
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