OCR F324 (Chains, rings and spectroscopy) 28/06/10

Reply 380

Chunkeymonkey62

2

_Andrew_

Anyone want to do a organic synthesis revision sesh, around 7.30 :teeth:

Questions, and problems etc..

Tonight?

Reply 381

_Andrew_

11

Chunkeymonkey62

Tonight?

Well, yes. Unless it interrupts with Eastenders or something :p:

?

Reply 382

TwirlGirl

15

_Andrew_

Anyone want to do a organic synthesis revision sesh, around 7.30 :teeth:

Questions, and problems etc..

yes, i will :smile:

Reply 383

Chunkeymonkey62

2

_Andrew_

Well, yes. Unless it interrupts with Eastenders or something :p:

?

I was going to mechanics. Will you be doing one tomorrow?

Reply 384

cyborg

I'll join in as well :biggrin:

7:30 then.

Reply 385

CertifiedAngel

10

_Andrew_

Anyone want to do a organic synthesis revision sesh, around 7.30 :teeth:

Questions, and problems etc..

yes and can we do analysis after. I have a feeling acid anhydrides, diazonium ions and kekule's structure might come up.

I know that carbon-13 will DEFINATELY come up, nmr and chromatography. And a question on one of CDCL3, TMS and D2O and optical isomers.

lol, i like predicting questions and tend to be quite good at that.

Reply 386

_Andrew_

11

CertifiedAngel

yes and can we do analysis after. I have a feeling acid anhydrides, diazonium ions and kekule's structure might come up.

I know that carbon-13 will definitely come up, nmr and chromatography. And a question on one of CDCL3, TMS and D2O and optical isomers.

lol, i like predicting questions and tend to be quite good at that.

I'm pretty sure acid anhydrides will be in the paper too, okay 7.30 is a chemistry date people :p:

Reply 387

AnthonyShock

13

I think Stretch and Challenge will be mainly incorperated into synthesis questions and NMR/IR/MS questions.
Could be wrong though.

Reply 388

Tariq786

12

im gunna cover all module 1 today. all practice and exam questions.

tomorrow will do the same for Modules 2 & 3. thats my plan! and after that if i have some time to spare do other practice exam questions.

Reply 389

_Andrew_

11

Have a go at..

Propene from propanal. Two steps. Reagents and conditions.....

Reply 390

jimber

9

reduce w/NaBH4 and then add h2so4 + reflux?

Reply 391

TwirlGirl

15

what equations from AS do we need to know? Or... which equations do we need to know that aren't in the A2 OCR Chem text book for Chem A?

Reply 392

_Andrew_

11

jimber

reduce w/NaBH4 and then add h2so4 + reflux?

Yep

Reply 393

CertifiedAngel

10

_Andrew_

Have a go at..

Propene from propanal. Two steps. Reagents and conditions.....

propene in the presence of h2so4 catalyst and steam
-high temp 300
- high pressure

forms propanol
-pronaol is oxidised in teh presence of k2cr2o7, and forms the aldehyde propanal and a water molecule is released. H2SO4 catalyst

Amirite?

Reply 394

CertifiedAngel

10

Explain how you could prepare an azo dye starting from nitrobenzene? [8 marks]
reagents, essential conditions and balanced equations!

I have the mark scheme answer to this, you can draw out the equations and thn check the book to see if you did it correctly :smile:

Reply 395

Robbie10538

9

CertifiedAngel

Explain how you could prepare an azo dye starting from nitrobenzene? [8 marks]
reagents, essential conditions and balanced equations!

I have the mark scheme answer to this, you can draw out the equations and thn check the book to see if you did it correctly :smile:

You could make it from Benzene too add another step :biggrin:

Reply 396

Woody.

12

CertifiedAngel

Explain how you could prepare an azo dye starting from nitrobenzene? [8 marks]
reagents, essential conditions and balanced equations!

I have the mark scheme answer to this, you can draw out the equations and thn check the book to see if you did it correctly :smile:

Would you mind linking the markscheme so I can check?

Reply 397

dpd5

nitrobenzene + reducing agent (HCl/Sn) to phenylamine.
C6h5no2 + 6(H) - C6h5nh2 +2 h20

Phenylamine + nitrous acid, hn02 (NaNo2 + hcl) - benzenediazonium chloride + 2 h2o
under 10 degrees

benzenediazonium chloride + phenol under alkaline conditions (presence of NaOH) - azo dye + NaCl + H20

Something along those lines?