The Student Room Group
Reply 1
Fenchurch
The circle C has equation x2 + y2 − 8x − 16y + 72 = 0.
a) Find the coordinates of the centre and the radius of C.

x^2 + y^2 − 8x − 16y + 72 = 0

a) x^2 - 8x + y^2 − 16y + 72 = 0
=> (x-4)^2 - 16 + (y−8)^2 - 64 + 72 = 0
=> (x-4)^2 + (y−8)^2 = 8

centre = (4, 8)
radius = sqrt(8)
b) Find the distance of the centre of C from the origin in the form kroot5.

sqrt(4^2 + 8^2) = sqrt80 = 4sqrt(5)
Reply 2
hi buddy how did you find out the length i assume you got it right just wondering the reason behind it thanks
Reply 3
The distance between two points is

sqrt (x2-x1)^2 + (y2-y1)^2
Reply 4
sqrt (x2-x1)^2 + (y2-y1)^2
of course nice1

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