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# -/+ Root Solutions

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1. The mark scheme lists the only solutions when 2 is divided by positive root 10

Why wouldn't the solutions where 2 is divided by negative root 10 be acceptable?

The mark scheme lists the only solutions when 2 is divided by positive root 10

Why wouldn't the solutions where 2 is divided by negative root 10 be acceptable?

The value obtained from the square root is always taken as positive.
3. maybe there is some limitation on x, like
4. This is from Core 4 but in some Core 3 questions for example,

There's a need to find the solutions for -root6 and +root6
5. (Original post by njl94)
maybe there is some limitation on x, like
Nope, the solutions for the negative root would also be acceptable
This is from Core 4 but in some Core 3 questions for example,

There's a need to find the solutions for -root6 and +root6

It is the same as

But

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