[pleasedtobeatyou]

The mark scheme lists the only solutions when 2 is divided by positive root 10

Why wouldn't the solutions where 2 is divided by negative root 10 be acceptable?

[raheem94]

(Original post by pleasedtobeatyou)


The mark scheme lists the only solutions when 2 is divided by positive root 10

Why wouldn't the solutions where 2 is divided by negative root 10 be acceptable?

The value obtained from the square root is always taken as positive.

[njl94]

maybe there is some limitation on x, like

[pleasedtobeatyou]

This is from Core 4 but in some Core 3 questions for example,



There's a need to find the solutions for -root6 and +root6

[pleasedtobeatyou]

(Original post by njl94)
maybe there is some limitation on x, like

Nope, the solutions for the negative root would also be acceptable

[raheem94]

(Original post by pleasedtobeatyou)
This is from Core 4 but in some Core 3 questions for example,



There's a need to find the solutions for -root6 and +root6

It is the same as

But