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Edexcel Unit 6b June 2005

Hiya,

I've done the question in section A but really not sure whether its the right answer or not, since i don't have the mark scheme... :frown:

Do you have any idea/answers to the whole of question 1??

Here are the answer i got:
1aii) slope: -0.018
bi) second order (overall)
bii) first one is Rate = k[S2O8^2-] [H3AsO3]
second one is Rate = k[S2O8^2-]2

and for the experiment, i just said keeping the conc of one reactant constant while double the other and measure the rate.

Thanks :wink:

Reply 1

Erana

I got exactly the same answer. Haven't got the mark scheme, but I think I remember going over it in class and it was the right answer.

Yeah I got that too

thats sounds good...but for 1bi), the methoud should be 0.06/0.018 right? which i got 3.3 something and how on earth do i get a ratio of 4:1 ???

Thanks again :smile: