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The Numberwang Thread

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n=0(1)n2n+1\displaystyle \sum_{n=0}^{\infty }\frac{(-1)^n}{2n+1}
Original post by rayquaza17
n=0(1)n2n+1\displaystyle \sum_{n=0}^{\infty }\frac{(-1)^n}{2n+1}


I don't know what that adds up to, but it's Numberwang in my book!

Next round: 24
This thread still kills me
Original post by Architecture-er
This thread still kills me


This thread has been dead for over half a year!

Unless we're actually going to try and revive it, lets leave it in peace.
Original post by spotify95
This thread has been dead for over half a year!

Unless we're actually going to try and revive it, lets leave it in peace.


Pfft the game is over, the appreciation continues in perpetuity
Forgot about this:tongue:

Posted from TSR Mobile
Original post by Andy98
Forgot about this:tongue:

Posted from TSR Mobile


Think everyone has, that's why the thread has died! That and the fact that no-one knows how to play it!

Think we'd better leave this alone now... It's been good while it lasted!
(edited 8 years ago)

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