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How do potential dividers and potentiometers work?

Also, may you explain question 6 part d from the following paper?

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s10_qp_22.pdf

Thank you in advance.
Original post by asadmoosvi
Also, may you explain question 6 part d from the following paper?

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s10_qp_22.pdf

Thank you in advance.


Hello and welcome to TSR. :smile:

Physics study help forum works by you explaining where your difficulty arises in understanding / showing your work so far. Then we give you guidance and hints so you can work out the corrct answer for yourself rather than simply giving you the answer which requires no work on your behalf.:tongue:

Soooooo..........

What is it about potential dividers you do not understand that needs clarification?

Q 6(d):

If the resistance wire is linear, then the resistance between both halves at the mid point will be equal. However, theres a matter of that pesky voltmeter internal resistamce.

Can you see how that might alter the voltmeter reading?
Reply 2
Original post by asadmoosvi
Also, may you explain question 6 part d from the following paper?

http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20%289702%29/9702_s10_qp_22.pdf

Thank you in advance.


in a fixed potential divider you have two fixed resistances (R1 and R2 in series with a supply voltage, Vsupply across the pair.

Because they're in series you know some things.
1. the total resistance Rtotal = R1 + R2
2. the current through both is the same and given by I = Vsupply / Rtotal

the voltage across a resistor is given by ohms law V=IR so the voltage across either resistor is given by Vx=Rx Vsupply/Rtotal
---
e.g. if Vsupply=10V
R1=7 ohm
R2=3 ohm
then
R total = 7+3 = 10 ohm
I = 10/10 = 1 amps
V1=R1 * Vsupply/Rtotal
=7*10/10
=7

you can repeat for R2 and then confirm that V1+V2=Vsupply as a sanity check

neat.

however it only works if the current in both resistors is the same, so is the current the same when that 5 ohm ammeter is poking about your circuit?
How about potentiometers- how do they work?
Original post by TaraStilton
How about potentiometers- how do they work?

Hello and welcome to TSR. :smile:

Potentiometers (variable resistor) are nothing more than a variable potential divider.

The two ends of the potentiometer have a resistor connected between them with the resistive element exposed (called the track) so that a third sliding conductor (wiper) is able to move along the track.

The output voltage is picked off by the wiper whose position along the track determines the ratio of the divided resistance.

Hey presto: variable potential divider.

Thanks!
First equation: V1 = IR1
Second equation: V2 = IR2

How do you divide the first equation by the second to get V1/V2 = R1/R2? What does dividing the first equation by the second equation mean?
Original post by TaraStilton
First equation: V1 = IR1
Second equation: V2 = IR2

How do you divide the first equation by the second to get V1/V2 = R1/R2? What does dividing the first equation by the second equation mean?


It means if, for example

y = 2x
and
z = 4x

You know z is 2 times bigger than y

In other words
y/z = 1/2

You can refer to this as dividing one equation by the other
y/z = 2x/4x

y/z = 1/2

This is what has been done in the example you have.
(edited 9 years ago)
Thanks

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