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Beryllium Chrloride + Sodium Hydroxide... what happens?
Hello!
I'm just doing some revision questions in prep for a chemistry exam, and i've come accross a question i've not seen before.
What happends (state and describe what you'd observe) if Beryllium Chloride reacted with Sodium Hydroxide.
What 'topic' (if you like), is this as it seems quite a generalised question?
We have to account for our descriptions, also.
Many thanks in advance!
I'm just doing some revision questions in prep for a chemistry exam, and i've come accross a question i've not seen before.
What happends (state and describe what you'd observe) if Beryllium Chloride reacted with Sodium Hydroxide.
What 'topic' (if you like), is this as it seems quite a generalised question?
We have to account for our descriptions, also.
Many thanks in advance!
t-a-r-online
Hello!
I'm just doing some revision questions in prep for a chemistry exam, and i've come accross a question i've not seen before.
What happends (state and describe what you'd observe) if Beryllium Chloride reacted with Sodium Hydroxide.
What 'topic' (if you like), is this as it seems quite a generalised question?
We have to account for our descriptions, also.
Many thanks in advance!
I'm just doing some revision questions in prep for a chemistry exam, and i've come accross a question i've not seen before.
What happends (state and describe what you'd observe) if Beryllium Chloride reacted with Sodium Hydroxide.
What 'topic' (if you like), is this as it seems quite a generalised question?
We have to account for our descriptions, also.
Many thanks in advance!
HCl is produced?
Yeah, i've got that far!!
It's a four mark question, so it wants a bit more, i think!
Thanks for replying!
It's a four mark question, so it wants a bit more, i think!
Thanks for replying!
HCl (very acidic gas) can't be produced from a strong base like sodium hydroxide!
It would react forming NaCl
Although the actual mix formed by reaction between BeCl2 and NaOH may contain several complex forms the main ion formed in strong NaOH is the [Be(OH)4]2- complex ion.
Hence:
BeCl2 + 4NaOH --> [Be(OH)4]2- + 2NaCl + 2Na+
What we have here is the beryllate II ion
It would react forming NaCl
Although the actual mix formed by reaction between BeCl2 and NaOH may contain several complex forms the main ion formed in strong NaOH is the [Be(OH)4]2- complex ion.
Hence:
BeCl2 + 4NaOH --> [Be(OH)4]2- + 2NaCl + 2Na+
What we have here is the beryllate II ion
Thanks for your reply, Charco. It's appreciated.
I'm just about there with it now, i think!
I'm just about there with it now, i think!
Although the actual mix formed by reaction between BeCl2 and NaOH may contain several complex forms the main ion formed in strong NaOH is the [Be(OH)4]2- complex ion
Are you sure it will form a complex ion?
I would say it forms NaCl and Be(OH)2 that is insoluble in water, with
Kso= 6,92 * 10 (-22)
but i agree that it definitely can't produce HCl
i think the reaction is:
2NaOH + BaCl2 ---> NaCl + Ba(OH)2
or, as it should be in a polar solvent, in the ionic form:
2Na+ + 2OH- + Ba2+ + 2 Cl- ----> 2 Na+ + 2 Cl- + Ba(OH)2
Like I said, the actual reaction is complex in that several species exist in solution such as:
[Be(H2O)]2+
[Be2(OH)]3+
[Be3(OH)3]3+
[Be5(OH)7]3+
The bonding is complicated with beryllium being pseudo tetrahedral with the Be involved in Be-O-Be, or Be-OH-Be bridges and even cyclic structures. The actual concentation of each species is dependent on temperature, concentration and pH
However, in strong alkali the beryllate iion predominates.
[Be(H2O)]2+
[Be2(OH)]3+
[Be3(OH)3]3+
[Be5(OH)7]3+
The bonding is complicated with beryllium being pseudo tetrahedral with the Be involved in Be-O-Be, or Be-OH-Be bridges and even cyclic structures. The actual concentation of each species is dependent on temperature, concentration and pH
However, in strong alkali the beryllate iion predominates.
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