C1 Co ordinate geometry
Part (Iii),I'm completely confused on how to do or approach it.
Original post by Kadak
Part (Iii),I'm completely confused on how to do or approach it.
lol? nothing there...
Original post by Kadak
Your picture doesn't show the full question
Original post by TenOfThem
Your picture doesn't show the full question
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Plus my workings to the previous parts.
Use pythagoras to set up an equation involving d
Distance^(2) = (x2-x1)^(2) + (y2-y1)^(2)
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Distance^(2) = (x2-x1)^(2) + (y2-y1)^(2)
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Do you get it fam
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Original post by dont ban me :(
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Nope,how would approach this question?
Original post by Kadak
He showed you in post 6
Do you know how to use Pythagoras to find the distance between two points?
Original post by Kadak
It's just application of pythagoras
You know the distance between the two points is 2√13. This is like your hypotenuse
So (2√13)^2 = change in x-values squared plus change in y-values squared
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Original post by dont ban me :(
It's just application of pythagoras
You know the distance between the two points is 2√13. This is like your hypotenuse
So (2√13)^2 = change in x-values squared plus change in y-values squared
Posted from TSR Mobile
You know the distance between the two points is 2√13. This is like your hypotenuse
So (2√13)^2 = change in x-values squared plus change in y-values squared
Posted from TSR Mobile
Oh.Thanks Q.
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