what is being oxidised in this equation? thanx
the question states that the above reaction is oxidation of the nitrite ion
Attachment not found
however i thought the nitrite and nitrate ions have the same oxidation number of -1
i see that the oxidation number of the nitrogen has changed from +3 to +5
i thought oxidation is an increase in oxidation number so how can it be the nitrite ion that is being oxidised? is it not just the nitrogen atom?
thnku in advance for any help
(edited 8 years ago)
It's the N that is oxidised
NO2- + H2O --> NO3- + 2H+ + 2e
NO2- + H2O --> NO3- + 2H+ + 2e
Original post by TeachChemistry
It's the N that is oxidised
NO2- + H2O --> NO3- + 2H+ + 2e
NO2- + H2O --> NO3- + 2H+ + 2e
Thnks
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