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For the zwitterion, of an amino acid, where there are 2 carboxylic acids, negative?

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Original post by z33
i just do textbook questions and what the teacher says


A sound philosophy ...
Reply 21
Original post by charco
A sound philosophy ...


works for the exams :3
Original post by charco
All of this is misleading, as the groups are all involved in equilibria.

The situation that exists when the molecule is neutral will correspond to the same amount of ionisation from the two carboxylic acid groups as from the protonated amine.

i.e. the SUM of the negative charges must equal the positive charge at the isoelectric point.


Hey can I just ask is that at the isoelectric point?
Original post by Mihael_Keehl
Hey can I just ask is that at the isoelectric point?


That's what it says ...
Original post by charco
That's what it says ...


:/

How can that happen, if the isoelectric point has no charge.
Original post by Mihael_Keehl
:/

How can that happen, if the isoelectric point has no charge.


You did not read my post carefully enough ...

The SUM of the negative charges equal the positive charge at the isoelectric point,

BUT the extent of the equilibria that produces each species is clearly not completely to the RHS.

The extent of each dissociation depends on the pKa value of each COOH proton.

Imagine one COOH group dissociated 95% and the other 5% then this would balance an NH3+ formed at 100%

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