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Why is it B and not C

Here is the question:

[

11 Hydrated chromium(III) chloride, CrCl3.6H2O, exists in several isomeric forms with varying numbers of chloro and water ligands.

A solution containing 0.10 mol of one of these isomers reacts with excess silver nitrate. 0.20 mol of silver chloride, AgCl, is precipitated immediately.
The formula of the complex ion in this isomer is

A [Cr(H2O)6]3+
B [CrCl(H2O)5]2+
C [CrCl2(H2O)4]+
D [CrCl3(H2O)3]

]

In the mark scheme the answer is B.

I think it is C because 1 molecule of the complex should provide 2 atoms of Cl to give the 0.1:0.2 ratio given between the complex and the AgCl.

What am I missing?

Thanks in advance!
1 mol of complex gives 2 mol of AgCl

CrCl3.6H2O dissolves in water to give [Cr(H2O)5(Cl)]2+ + 2Cl- + H2O

hence B
Ahaaa

Thank you BobbJo
Reply 3
i didnt get it?
Original post by riamu
i didnt get it?

The silver ions only react with the chloride ions that are NOT part of the complex ion.

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