Hi Kittymity,
The answer can’t be A or B as oxidation with potassium dichromate and primary alcohol produces aldehydes when solution is heated gently. Not reflux. When primary alcohols are refluxed the product is a carboxylic acid. When secondary alcohols react with acidified potassium dichromate under reflux, the product is a ketone. So the answer is C. Hope that helps.
The answer can’t be A or B as oxidation with potassium dichromate and primary alcohol produces aldehydes when solution is heated gently. Not reflux. When primary alcohols are refluxed the product is a carboxylic acid. When secondary alcohols react with acidified potassium dichromate under reflux, the product is a ketone. So the answer is C. Hope that helps.
Hey,
I know I'm like a year late but lets do this.
The reflux of A, would form C5H10O2 as the alcohol is tertiary, therefore cannot change, and the double O bond is an aldehyde which would turn into a carboxylic acid, making the overall formula C5H10O2
The reflux of B, would form C5H8O3 as the secondary alcohol is turned into a ketone, and the aldehyde turns to carboxylic acid, so it has 1 too many oxygen.
The reflux of C however, would create a ketone on the secondary alcohol, and the already existing ketone would remain a ketone. This brings the molecular formula to C5H8O2.
I doubt you will ever have these issues again, but in the case of struggle, try drawing out the skeletal product and counting the carbon, hydrogen and oxygen. This is how I solved it.
Kindest Regards!
I know I'm like a year late but lets do this.
The reflux of A, would form C5H10O2 as the alcohol is tertiary, therefore cannot change, and the double O bond is an aldehyde which would turn into a carboxylic acid, making the overall formula C5H10O2
The reflux of B, would form C5H8O3 as the secondary alcohol is turned into a ketone, and the aldehyde turns to carboxylic acid, so it has 1 too many oxygen.
The reflux of C however, would create a ketone on the secondary alcohol, and the already existing ketone would remain a ketone. This brings the molecular formula to C5H8O2.
I doubt you will ever have these issues again, but in the case of struggle, try drawing out the skeletal product and counting the carbon, hydrogen and oxygen. This is how I solved it.
Kindest Regards!
Quick Reply
Related discussions
- Hey
- Chemistry OCR B Depth in Chemistry AS Levels Paper 2023
- iDEA silver badge entrepreneur
- TSR Study Together - STEM vs Humanities!
- London south bank university Hygiene
- A level options
- AQA A Level Chemistry Paper 1 Practicals
- Help maths
- A level subjects help for med/dent
- What subjects do I take?
- MY GYG
- Dissertation Survey
- A Level Options?
- MSc Speech & Language Therapy (Pre-registration) at BCU/Birmingham City University
- my gyg journey
- Medicine Applications for 2024 entry
- Chem a level
- sz's academic transformation journey!⭐ ~ gyg
- Holding myself accountable; study!
- cambridge physical natsci
Latest
Trending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these productsTrending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these products
