If the earth has a charge of 1.0 × 10^6 C, find the B-field at the sun due to the motion of the
earth, given that the earth’s velocity relative to the sun is 30 kms−1 and the radius of the
earth’s orbit is 1.5 × 10^11 m
edit: so i have tried using E = kq/r^2= (8.99x10^9)(1x10^6)/(1.5x10^11)^2
that gives 3.995.....x10^-7
Then i use V = E /B ==> B = E / V
B = 3.995 x 10^-7 / 30000
i get B = 1.33 x 10^-11
but the answer is 1.3 x 10^-19
where have i gone wrong
Thanks