Variable Acceleration

Acceleration is related to displacement, because I need to find acceleration to be able to find displacement? Since the equation S=ut 0.5at^2So how do I start of though? Sub in 10 for t in the equation given? That would be a=1/500(2000-1000) which equals to acceleration is 2ms^-2

There us a relation using calculus.
You must have covered it on your A level?

integrate twice?

Yes, I was hoping the OP would realise this.

so integrate twice, then what? I know you have to sub in t=0 s=0 but what second set of values do I use to find the constants from the integration before substituting in t=10 to find the distance

You integrate once to get velocity then again to get distance or displacement. So you have initial conditions in each case.

Note its better to start your own thread rather than bump an old one.

You integrate once to get velocity then again to get distance or displacement. So you have initial conditions in each case.

Note its better to start your own thread rather than bump an old one.