Chemistry equation

Sanjetti

Oh and EierVonSatan, I'm guessing you do a chemistry degree?

Got one

, doing another :s-smilie:

Reply 21

Malsi101

Copper Hydroxide =

Cu^{2+} + OH^-

therefore to balance the charge, we will need two OH^-'s thus we get

Cu^{2+} + 2OH^- = Cu(OH)_2

when 2's are involved :frown:

Everything needs to be equal and stable. Therefore, the charges need to add up to 0 for each compound.

Cu^{2+}

is Copper (II), meaning that it's Copper (chemical symbol Cu) and it is a cation (meaning it's positive) with a charge of +2 - it has two electrons missing so overall it is more positively charged than negatively charged (remembering electrons are negative, protons are positive)

OH^-

is OH (Hydroxide) and has a charge of -1, meaning that it has one too many electrons (making the overall charge negative).

If you want to add them both together to make a neutral compound, you need to add 2 electrons to the Copper (II). If you just added a single OH^-, the overall charge wouldn't equal one.

Bearing this in mind, you need to do

Cu^{2+} + 2OH^-

which gives you

Cu(OH)_2

Reply 22

DeanK2

Maths is the real discipline - stop worrying about balancing your equations.

Reply 23

no I copied and pastes sohansha's post to show you what I don't get :p:

glad you've given me one to try as I was going to just ask you to :biggrin:

ok here goes

Cu^{2+} + NO_3^{-} --> Cu^{2+} + 2NO_3^{-} = Cu(NO)_3

after reading Beska's ever so helpful post I edited and now have the following q;s :smile:

Why do we put brackets in instead of just saying

CuNO_3

Why do we put the 2 in front of the Formulae instead of putting it after

Unparseable latex formula:

NO_3^{-}_2

Oh and this is not cos I'm dumb( :p:

) rather only did my GCSE's in one year and didn't cover much :frown:

Reply 24

EierVonSatan

Got one

, doing another :s-smilie:

Nice! Well done, and congrats :smile:

. What's your second one on?

Reply 25

Kyalimers

Anyone need any more help with Compound Formulas??

Reply 26

DeanK2

You had 2NO3(-) - why didn't you bracket and subscript 2 in the final part?

Reply 27

Malsi101

no I copied and pastes sohansha's post to show you what I don't get :p:

glad you've given me one to try as I was going to just ask you to :biggrin:

ok here goes

Cu^{2+} + NO_3^{-} --> Cu^{2+} + 2NO_3^{-} = CuNO_3

You were nearly there! Remember its Cu(NO3)2, as you've put a 2 in from of the NO3- in the middle part of your equation

Reply 28

Malsi101

I made myself a cheat sheet to use for balancing/writing equations, I'm sure it'd be useful to you too:

http://www.beska.net/ions.pdf

Edit: Wow, I just noticed mistakes on there. Let me fix those. Fixed.

I have it printed out and stuck to the front of my chemistry folder, along with the solubility rules. :smile:

Reply 29

Once you've got GHOSH-5's question right, here's probably the most difficult ones they can test:

Aluminium sulphate (Hint: the constituent ions are Al3+ (carries a 3+ charge) and SO4 2- (carries a 2- charge))

(sorry about the lack of latex)

Answer once you've tried it:

Spoiler

Reply 30

Beska

I made myself a cheat sheet to use for balancing/writing equations, I'm sure it'd be useful to you too:

http://www.beska.net/ions.pdf

I have it printed out and stuck to the front of my chemistry folder, along with the solubility rules. :smile:

wow that is really helpful...rep tomorrow :^_^:

Reply 31

Sanjetti

Once you've got GHOSH-5's question right, here's probably the most difficult ones they can test:

Aluminium sulphate (Hint: the constituent ions are Al3+ (carries a 3+ charge) and SO4 2- (carries a 2- charge))

(sorry about the lack of latex)

how do you do balance an equation which has one ion with a 3+ charge and another with a 2- charge :eek4:

Reply 32

Beska

I made myself a cheat sheet to use for balancing/writing equations, I'm sure it'd be useful to you too:

http://www.beska.net/ions.pdf

Edit: Wow, I just noticed mistakes on there. Let me fix those. Fixed.

I have it printed out and stuck to the front of my chemistry folder, along with the solubility rules. :smile:

you better not be giving me wrong data :cry:

Reply 33

Kyalimers

Hmm let me see If I can make a variable expression somehow:

Find the Compound Formula for AB where

A^{x+} , B^{y-}

Step 1. Find

x - y

Step 2. If the above does not equal 0, then work out, how many x's and/or how many y's will be required to make

k_1 x - k_2 y = 0

Step 3. Put

k_1

before A and

k_2

after B thus:

k_1 A^{x+} , (B^{y-})_{k_2}

Step 4. Put the ions together:

k_1 A^{x+} , k_2 B^{y-} \rightarrow k_1 A (B)_{k_2}

where

k_1

and

k_2

are integers.

Reply 34

Yeah, is one of them saying that N3- is a nitRATE ion ? :p:

Reply 35

Oxy

14

Malsi101

how do you do balance an equation which has one ion with a 3+ charge and another with a 2- charge :eek4:

2 of the 3+ charge and 3 of the -2 Charge...both cancel out.

Just use multiples if u dont cancel out immediaetly try multiplying by 2 or 3 or even 4 sometimes to get the charges to equal 0

Reply 36

Malsi101

you better not be giving me wrong data :cry:

I didn't notice before, but when I made it instead of going to edit the subscript of each ion over and over, I just copied and pasted and changed the charge/element. I must have had a brain fart and didn't change Aluminum's symbol - it was still "Ca3+". I've changed it now, though. :p:

Reply 37

Malsi101

how do you do balance an equation which has one ion with a 3+ charge and another with a 2- charge :eek4:

I've included a spoiler in my post if you want to see how to do it. Once you get the hang of it, it becomes much easier, I promise.

Reply 38

Sanjetti

Yeah, is one of them saying that N3- is a nitRATE ion ? :p:

Fixed that too, anyway. :smile:

Reply 39