Chemistry Please help

CaCO3 + H2O2  CaO2.xH2O + CO2 + H2O

Since excess hydrogen peroxide was present, the theoretical yield is based on the quantity of calcium carbonate used in the synthesis.

RMM of calcium carbonate = 72 g mol-1
Calcium carbonate used = 10.6 g Moles calcium carbonate used = 0.14623 mol [4 marks]

The number of moles of CaCO3 used is called the REACTION SCALE. How many moles of calcium peroxide hydrate will be produced from this number of moles of CaCO3 assuming that the reaction goes to completion (i.e. giving 100% of product or the ‘theoretical yield’)? Show your reasoning/calculation. [4 marks]

Reply 1

scimus63

9

1 mole of CaCO3 is 100g, (40 + 12 + 48) not 72!

The number of moles of calcium carbonate used is 10.6/100 = 0.106 moles.

SInce 1 mole of CaCo3 produces 1 mole of CaO2.xh2o then

since you started with 0.106 moles of CaCo3 you will get this number of moles of the hydrated calcium oxide

Reply 2

Mooonshine

OP

6

Original post by scimus63

1 mole of CaCO3 is 100g, (40 + 12 + 48) not 72!

The number of moles of calcium carbonate used is 10.6/100 = 0.106 moles.

SInce 1 mole of CaCo3 produces 1 mole of CaO2.xh2o then

since you started with 0.106 moles of CaCo3 you will get this number of moles of the hydrated calcium oxide