Hi, I'm kinda lost on this part of a muti sub part questions. I don't want to assume that 12V is across the 25 ohm resistor and then use the V=IR formula.
the questions mentions that the max resistance is 25 ohms and the minimum reading on the voltmeter is 0.75 v
The resistance. I didnt mention before but P can slide and is mounted on a copper bar.Component P can slide between X and Y. And the 0.75v reading is when is P moved and is the lowest value.
The resistance. I didnt mention before but P can slide and is mounted on a copper bar.Component P can slide between X and Y. And the 0.75v reading is when is P moved and is the lowest value.
You need to find the current in the circuit using V=IR
You need to find the current in the circuit using V=IR
12 = I x 25
I = 12/25 A
Sub this into V=IR for the lamp
0.75 = 12/25 x R
R = 1.6 ohms
Thanks for the reply,really appreciate it
I initially did this and only got 1 mark out of 2 or 3. I read the examiners read report for the questions and it states "Student assumed that the 12 V was across the 25 Ohm resistor".