vertical motion

A stone is thrown vertically upwards from ground level with speed of 12ms.
a. find the distance travelled by the stone during the first 2 seconds of its motion. (answer is 10meters...how?)
b. for how long is the stone more than a metre above ground level?

I can't work these out. I've worked out the max height above ground is 7.3m and the time taken to reach max height is 1.2s.

Can anyone please help.

a) Distance travelled is distance upwards + distance downwards.
b) Solve for the times when its 1m high and subtract them. Equivalently double the time it takes from 1m height to the max height, or ...

Thanks, I have now worked out the first part. I am still struggling with the second part.

Thanks, got it now!