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Kinematics

A Motorcyclist travels on a straight road with a constant acceleration of 0.6 ms^-2
P and Q are two points on the road 120m apart. Given that the motorcyclist increases speed by 6 ms^-1 between these two points as she travels from P to Q find:
a) The time taken to travel from P to Q

Somebody help with this question.
Reply 1
Which suvat may be appropriate here (write down clearly what youre given).
Reply 2
I think S=ut + 1/2at^2
S=120 , U=6 , A=0.6 , t= ? Is that correct?
(edited 4 months ago)
Reply 3
Original post by Josephbrian
I think S=ut + 1/2at^2
S=120 , U=6 , A=0.6 , t= ? Is that correct?

You dont know u, as youre told the velocity increases by 6m/s over that time, so it cant be that one. Think about which suvats involve acceleration and time and whether you know the other "two" things.
Reply 4
Original post by mqb2766
You dont know u, as youre told the velocity increases by 6m/s over that time, so it cant be that one. Think about which suvats involve acceleration and time and whether you know the other "two" things.

S=vt - 1/2at^2. Or v=u + at that’s if u is 0. So which is it and what are the values for suvat?
Reply 5
Original post by Josephbrian
S=vt - 1/2at^2. Or v=u + at that’s if u is 0. So which is it and what are the values for suvat?

Id rearrrange v=u+at and note that 6 is the change in velocity so ...
Reply 6
Original post by mqb2766
Id rearrrange v=u+at and note that 6 is the change in velocity so ...

Is it like this 6=0+0.6*t to get 10s ? What is ur answer for question?
Reply 7
Original post by Josephbrian
Is it like this 6=0+0.6*t to get 10s ? What is ur answer for question?

Yes, though its incorrect to assume u=0. You should really just write it down as the definition of (constant) acceleration is
acceleration = change in velocity / change in time
so
0.6 = 6/t
The v=u+at is the basic gcse suvat which wraps that up.
(edited 4 months ago)
Reply 8
Original post by mqb2766
Yes, though its incorrect to assume u=0. You should really just write it down as the definition of (constant) acceleration is
acceleration = change in velocity / change in time
so
0.6 = 6/t
The v=u+at is the basic gcse suvat which wraps that up.

Wow thanks, idk why it’s a 5 mark question just for that.

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