Kinematics Help
Could anyone point me in the right direction for how to do c)?
Cars A and B are travelling in the same direction along a straight road. The time t is in seconds.
At t = 0, car A is at rest. It accelerates at 3 ms-2 for 0t 10 and then travels at a constant speed.
Car B travels at 15 ms-1 for 0 t 30 and then accelerates at 1 ms-2 until it reaches a speed of 25 ms-1, after which it continues at this constant speed.
(a) Draw v-t diagrams for the motion of car A and of car B, where v is the speed in ms-1 and 0t 80.
[4]
(b) Show that, in the first 40 seconds, car A travels 400 m further than car B. [4]
(c) Given that car A is 500 m behind car B at t = 0, at what value of t does car A catch up with car B
Cars A and B are travelling in the same direction along a straight road. The time t is in seconds.
At t = 0, car A is at rest. It accelerates at 3 ms-2 for 0t 10 and then travels at a constant speed.
Car B travels at 15 ms-1 for 0 t 30 and then accelerates at 1 ms-2 until it reaches a speed of 25 ms-1, after which it continues at this constant speed.
(a) Draw v-t diagrams for the motion of car A and of car B, where v is the speed in ms-1 and 0t 80.
[4]
(b) Show that, in the first 40 seconds, car A travels 400 m further than car B. [4]
(c) Given that car A is 500 m behind car B at t = 0, at what value of t does car A catch up with car B
(edited 11 months ago)
(I haven't really pen-and-paper it)
There are quite a few approaches to it, including some heavy machinery like integration. But here are some initial observations:
- 400m in part (b) is a useful hint here, because that means we only really care about how the cars travel during the last 500m - 400m = 100m.
- 40s in part (b) is actually quite well chosen, since...
- Also sanity check - car A should travel faster than car B after t=40s (why? Perhaps explaining in 2 ways would convince yourself?)
There are quite a few approaches to it, including some heavy machinery like integration. But here are some initial observations:
- 400m in part (b) is a useful hint here, because that means we only really care about how the cars travel during the last 500m - 400m = 100m.
- 40s in part (b) is actually quite well chosen, since...
Spoiler
- Also sanity check - car A should travel faster than car B after t=40s (why? Perhaps explaining in 2 ways would convince yourself?)
(edited 11 months ago)
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