Cartesian Equations

https://www.quora.com/profile/Bravewarrior/p-146999616
Here is the question and its solution. Can someone please explain the solution to 6a? Thanks!

Reply 1

mqb2766

Original post by pigeonwarrior

https://www.quora.com/profile/Bravewarrior/p-146999616
Here is the question and its solution. Can someone please explain the solution to 6a? Thanks!

Its a reciprocal and a quadratic for x(t) and y(t). You should be able to sketch those, so have a try and post what you think?

Reply 2

pigeonwarrior

Original post by mqb2766

Its a reciprocal and a quadratic for x(t) and y(t). You should be able to sketch those, so have a try and post what you think?

(1) Quora - A place to share knowledge and better understand the world
Hello, this is what I have drawn 🙂

Reply 3

mqb2766

Original post by pigeonwarrior

(1) Quora - A place to share knowledge and better understand the world
Hello, this is what I have drawn 🙂

Agree, so do you understand the answers? Note Id not have excluded -3 for the quadratic y as it corresponds to t=2.

Edit - note your axis labels should really be x(t) and y(t)

(edited 2 months ago)

Reply 4

pigeonwarrior

Original post by mqb2766

Agree, so do you understand the answers? Note Id not have excluded -3 for the quadratic y as it corresponds to t=2.

For the range of x, it says x cannot be 2. But when x=2, the corresponding y-value is 3.5 and (2,3.5) are coordinates on the graph of y=3/x +2? This is what I am confused about 😟

Reply 5

mqb2766

Original post by pigeonwarrior

For the range of x, it says x cannot be 2. But when x=2, the corresponding y-value is 3.5 and (2,3.5) are coordinates on the graph of y=3/x +2? This is what I am confused about 😟

x(t) cannot be 2 as it corresponds to a horizontal asymptote on your graph. For the function y(x) this corresponds to a division by zero when x=2.

But y(t) when t=2 is -3.

Reply 6

pigeonwarrior

Original post by mqb2766

x(t) cannot be 2 as it corresponds to a horizontal asymptote on your graph. For the function y(x) this corresponds to a division by zero when x=2.

But y(t) when t=2 is -3.

Ohhh yes, it makes much more sense now, thank you!!!