Results are out! Find what you Get quick advice or join the chat
Hey! Sign in to get help with your study questionsNew here? Join for free to post

Leibnitz Theorem

Announcements Posted on
Talking about ISA/EMPA specifics is against our guidelines - read more here 05-03-2015
  1. Offline

    Hi, Im finding trouble trying to understand the Leibnitz theorem, can anyone help and just try simplifying it for me, Im just not getting it!:mad:

    I got these 2 questions:
    Use Leibnitz theorem to compute the 5th derivative of:
    a) x^3cos(x)
    b) x^2ln(x)

  2. Offline

    This looks not fun. Is it the same as what this page is describing

    If so letting u(x) = x^3 and v(x) = cos(x), I'd then find the 1-5 th derivatives of each of them, then just stick it in that big sum formula.
  3. Offline

    Yeah we have to use the formula given at the top of the page but I dont really understand it.
  4. Offline

    I'll try write out the first few stages of the first one then.

    You have  x^3 \cos x so split this into two (easily differentiable) functions  u(x) = x^ and  v(x) = \cos x . Find their 1st, 2nd, ..., 5th derivatives and just keep them somewhere handy.

    Now do you understand the sum notation? This is what you'd do using the formula (I'm not going to write it out, I don't know the symbols)

    Firstly, in the big sum, r = 0, and n = 5 because you want the 5th derivative.
    So you get (5C0 is 5 choose 0, the binomial thingy)
     5C0 \ x^3 \frac{d^5 (cos x)}{dx} = - x^3 \sin x
    And now r = 1 so
     5C1 \frac{dx^3}{dx} \frac{d^4 (cos x)}{dx^4} = 15x^2 \cos x
    And now do this for r= 2, 3, 4, and 5.
    Finally add up all those bits because its a sum. Hopefully some stuff cancels out too.
  5. Offline

    It's just the same as using the binomial theorem but substituting in derivatives, what part of it don;t you understand
  6. Offline

    Yeahh I think I get it now, I jus wasnt sure about the 'r' and 'n' term things. Thanks alot though
  7. Offline

    Sebbie I think I get it now, thanks
  8. Offline

    if you were to find the odd derivatives how would you do that?


Submit reply


Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?
  2. this can't be left blank
    this email is already registered. Forgotten your password?
  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By joining you agree to our Ts and Cs, privacy policy and site rules

  2. Slide to join now Processing…

Updated: December 5, 2010
2015 general election
New on TSR

Loved by Students

Our big survey results unveiled

Article updates
Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.