I'll try write out the first few stages of the first one then.
You have so split this into two (easily differentiable) functions and . Find their 1st, 2nd, ..., 5th derivatives and just keep them somewhere handy.
Now do you understand the sum notation? This is what you'd do using the formula (I'm not going to write it out, I don't know the symbols)
Firstly, in the big sum, r = 0, and n = 5 because you want the 5th derivative.
So you get (5C0 is 5 choose 0, the binomial thingy)
And now r = 1 so
And now do this for r= 2, 3, 4, and 5.
Finally add up all those bits because its a sum. Hopefully some stuff cancels out too.