The Student Room Group
Reply 1
Differentiate x with respect to t, then differentiate y with respect to t. Then use the chain rule.
ok but i really dont get it do i have to separate them for this one

x=2t-sin2t

will i need to use the double angle formula then differentiate that?
Reply 3
No, you use the chain rule to differentiate sin2t.

You should be comfortable using the chain rule by the time you come to this topic.
well im not comfortable with it! im so confused think ill just give up thanks anyway.
Reply 5
Then parametric differentiation is probably best left for a while.

If x=sin2t, let u=2t so du/dt=2, x=sinu so dx/du=cosu=cos2t and dx/dt=(dx/du)*(du/dt)=2cos2t.

Ring any bells?
yeh thats what i got when i was just working out :smile::smile: thanks. So would x = 2t-sin2t

dx/dt = 2-2cos2t
sweet_candy_cane
yeh thats what i got when i was just working out :smile::smile: thanks. So would x = 2t-sin2t

dx/dt = 2-2cos2t


Yep.
ghostwalker
Yep.


thankyou!
would y = 1-cost

dy/dt = sint
sweet_candy_cane
thankyou!
would y = 1-cost

dy/dt = sint


Yep to that one too.
ghostwalker
Yep to that one too.


sorry! last 2 questions!


would x = 3t-2sint

dx/dt = 3-2cost

and y= t(squared) + tcost

dy/dt = 2t - t(sqaured)sint

???
sweet_candy_cane
sorry! last 2 questions!


would x = 3t-2sint

dx/dt = 3-2cost

and y= t(squared) + tcost

dy/dt = 2t - t(sqaured)sint

???


First one is correct.

For the second one, second part, you need use the product rule to differentiate "t Cos t".

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