Rate of cooling.

Hey,

In one of my chemistry experiments, I had to record temperature with time, and I got confused now on how to find the Final temperature by extrapolating the "downward slope" in temperature after the heat source is removed.

Is it enough to just find the linear fit of the cooling part, and extrapolate it?
And should I find the linear fit from the part it slopes down, or when the heat source was shut off?

THANK YOU!!! :woo:

Reply 1

Student#1

Anyone?

Reply 2

Student#1

41 views and no replies?

Please guys :frown:

Reply 3

charco

Study Forum Helper

Student#1

41 views and no replies?

Please guys :frown:

42...

Reply 4

chemicalguy

Think of it like an initial rate - find the gradient of the tangent at t=0 so the gradient at the steepest part

Reply 5

chemicalguy

Ie point the heat source removed

Reply 6

Shayke

Should do a tangent from the very start when the heat source was removed and extrapolate that. That's the initial rate of cooling.

Reply 7

Student#1

But the heat from the can goes to the water, and that takes time right?

So shouldnt the line be from the end point to the tangential point (inflexion) and extrapolated to t=0??