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Joint pdf - find C

The joint probability density function is:
Cexp(x)exp(y)Cexp(x)exp(y)

The C is a constant.

The ranges are x<1, y<1, x+y>1

They're supposed to be less than or equal to, greater than or equal to.

I am trying to find what the constant C is.

I know the method as I have done similar questions before but this one doesn't seem to be working out for me.

My method: integrate Cexp(x)exp(y)Cexp(x)exp(y), first with respect to y in between 1-x and 1.

This gives me Cexp(x)(exp(1)exp(1x)Cexp(x)(exp(1) - exp(1-x)

I find that odd already with the exp(1)exp(1).

Then integrating again with respect to x between 0 and 1, I get C(exp(2)+1) C (exp(2) +1)

As the joint pdf equals one, this then gives me C=1exp(2)+1 C = \frac{1}{exp(2)+1}

Doesn't look right to me...

Can someone please point out where I went wrong?
Original post by Mathlete29
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Agree with your limits.

After integrating wrt y, I get ex+1ee^{x+1}-e

and then after integrating wrt x, I get e22e e^2-2e

Edit: Both times C, of course.
(edited 11 years ago)

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