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M3 Vertical circles

Circle with radius r.
Mass is attached to one end of a rod and other end centre of circle.
Rod turns an angle theta from the bottom of the circle.

So if the circle has ... never mind I got it.
(edited 7 years ago)
Reply 1
Original post by AlmostNotable
Circle with radius r.
Mass is attached to one end of a rod and other end centre of circle.
Rod turns an angle theta from the bottom of the circle.

Resolving to find Tension I can get Tcos(theta)=mg and T=mgcos(theta)

Which is right and why?


I can't quite get what you're asking, but:



Means that if you resolve radially inwards, you get: Tmgcosθ=FcT - mg\cos \theta = F_c where FcF_c is the centripetal force.
Original post by Zacken
I can't quite get what you're asking, but:



Means that if you resolve radially inwards, you get: Tmgcosθ=FcT - mg\cos \theta = F_c where FcF_c is the centripetal force.


Do we need to know how to find escape velocity for M3?
Reply 3
Original post by AlmostNotable
Do we need to know how to find escape velocity for M3?


Nope.
Whut...?

Edit: Seems you got it :redface:
(edited 7 years ago)
Original post by Zacken
Nope.


Why did I revise that then?
Reply 6
Original post by AlmostNotable
Why did I revise that then?


I dunno, you need to know it for U5 Edexcel physics.

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