Original post by LorryBalls
what paper is this?
I got 0.3 J but I don't know if its right
I found the extension by using the formula f=kx solving for x
x= 0.2
then i used e= 1/2kx^2
e = 1/2*15*02 = 0.3 J
I found the extension by using the formula f=kx solving for x
x= 0.2
then i used e= 1/2kx^2
e = 1/2*15*02 = 0.3 J
Yes, that's the correct answer. See the marking scheme at http://filestore.aqa.org.uk/resources/physics/AQA-74072-SMS.PDF (last page).
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