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Quick Trig Question

Arbitrage

If Arctan(x/y) = 270, How would I go about finding just the value of x/y??

Thank you.

Reply 1

Swayum

If arctan(z) = 270, what's z?

Reply 2

Nfixlol

arctan (\frac{x}{y}) = 270

is the same as:

tan 270 = \frac{x}{y}

Swayum

If arctan(z) = 270, what's z?

btw both your PSes are :coma:

i need some kinda inspiration if i intend to make mine anywhere near as good :sigh:

Reply 3

Arbitrage

Lol, I knew it!

But one more question please, when you do tan(270) you get 1.963. When you do the inverse process and put arctan(1.963) you get 70... I know it has something to do with the fact the tan graph is periodical, but i just want to confirm it. Thanks.

Reply 4

Swayum

Argh, I didn't realise you said arctan(x/y) = 270. That doesn't work. Are you sure it's 270? But yeah, in general, you will run into problems with inverse trig functions because they're defined over the -90 to 90 range to make them one to one functions (because tan(1) = tan(181) = tan(361) = tan(-179) etc)

Nfixlol

btw both your PSes are :coma:

i need some kinda inspiration if i intend to make mine anywhere near as good :sigh:

Thanks a lot :smile:

. When you come up with something, make sure to post it in TSR's PS help section. They should give you some advice.

Reply 5

Arbitrage

Wait sorry not 270, it was 135, my mistake. 135 = Arctan(z)

Reply 6

Nfixlol

tan 90 = tan 270

the tan graph has a time period of 180 degrees, or

\pi

radians.

are you sure you read the question right? because tan270 and tan90 are both vertical asymptotes

edit: okay i've only just seen your new post, but anyway