NEED HELP with physics!! (Pressure)

the pressure inside the tyre is 3 x10^5 N/m^2

after a period of time the temperature has dropped 20 degrees to 15 degrees

what is the new pressure? assuming the volume of the tyres remains constant

PLEASE EXPLAIN SO I UNDERSTAND RATHER THAN JUST DOING IT FOR ME!!

Use P_1V/T_1=P_2V/T_2
since V is constant they bth cancel out
and youre left wit
P_1/T_1=P_2/T_2
can you find the new pressure now?
remember T is in K

no

what is _ and what is V?????

i did that to distinguish the two pressures (since Latex not working)
P1 and P2 (reads pressure 1 and pressure 2)
V is the volume ( there is no need to distinguish as the volume is constant they will be same )

ok thanks

will try and figure it out from here

The temperature must be on the Absolute Scale. So 20 degrees becomes 293 and the 15 becomes 288

I did mention that in my op.

OK, I didn't notice.