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C1 quadratic equations with K help please!

I cant do any of the questions in exam papers about quadratic equations with K involved. :eek3: And the exam is tomorow!
Can anyone help me with how they work please?
Here is one I cant do:

a, Simplify (k+5)^2 - 12K(K+2)

b, The quadratic equation 3(K+2)x^2+(K+5)x+k=0 has real roots.
i, Show that (K-1)(11K+25) <0 (Less than or equal to 0)
ii, Hence find possible values for K

Help please!!!
Reply 1
a) expand them both out
then try and simplify
so its:
k^2 + 10k + 25 - (12k^2 + 24k) <-- be careful about the minus!!

so k^2 + 10k + 25 - 12k^2 - 24k

-11k^2 - 14K + 25
Reply 2
a) Expand out.. and simplify

b) i) What can you do to find out about the roots of a quadratic equation ? Think about the inequality...

ii) Draw a sketch of the quadratic, for what values of k is (K-1)(11K+25) < 0 look at the graph.
Reply 3
lol i just did this question:

b) discriminant > 0
b^2-(4*a*c) > 0
sub in from the question and rearrange
tadaa!

ii) factorise and then draw a graph as you should always do with quadratic inequalities
Reply 4
Oh so do I use discriminant for b?
Reply 5
avsmithy
lol i just did this question:

b) discriminant > 0
b^2-(4*a*c) > 0
sub in from the question and rearrange
tadaa!

ii) factorise and then draw a graph as you should always do with quadratic inequalities


oh didnt see this
Reply 6
Im still stuck on b i
Do i use values from 3(K+2)x^2+(K+5)x+k=0 for discriminant? I dont see how it can work :s-smilie:
Reply 7
yep,
(k+5)^2 - (4*3(k+2)*k)
==>(k+5)^2-12k(k+2) --------which is what you simplified in a!
so work this through with the discriminant >=0
Reply 8
George88
Im still stuck on b i
Do i use values from 3(K+2)x^2+(K+5)x+k=0 for discriminant? I dont see how it can work :s-smilie:

Let a=3(k+2),b=k+5,c=ka=3(k+2),\, b=k+5,\, c=k, then the discriminant is b24acb^2-4ac. Write down b24acb^2-4ac in terms of kk and it should seem somewhat familiar.
Reply 9
Ohhhhhh i got it its the same as part a - I forgot the 3 >_>
but how does this show that it's greater than 0?
Reply 10
Oh never mind i got it - it says it has real roots
Thanks!!!

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